Consider the following reaction: 3CH4 + 2H2O + CO2 --> 4CO + 8H2
If the rate of disappearance of CO2 is 7.4 M/s, match the remaining compounds with their respective rates of appearance or dissapearance.
Chemistry question plz help!!?
2016-05-31 1:23 am
回答 (2)
2016-05-31 1:59 am
3CH₄ + 2H₂O + CO₂ → 4CO + 8H₂
The rate of disappearance of CO₂ = 7.4 M/s
The rate of disappearance of CH₄ = (7.4 M/s) × 3 = 22.2 M/s
The rate of disappearance of H₂O = (7.4 M/s) × 2 = 14.8 M/s
The rate of appearance of CO = (7.4 M/s) × 4 = 29.6 M/s
The rate of appearance of H₂ = (7.4 M/s) × 8 = 59.2 M/s
The rate of disappearance of CO₂ = 7.4 M/s
The rate of disappearance of CH₄ = (7.4 M/s) × 3 = 22.2 M/s
The rate of disappearance of H₂O = (7.4 M/s) × 2 = 14.8 M/s
The rate of appearance of CO = (7.4 M/s) × 4 = 29.6 M/s
The rate of appearance of H₂ = (7.4 M/s) × 8 = 59.2 M/s
2016-05-31 1:36 am
Since the coefficient of carvon dioxide is 1, multiply 7.4 moles/sec by respective coefficients.
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