Calculate the mass of sulfuric acid that is produced if all 43.3 grams of hydrochloric acid is consumed in the reaction. :)?

Molar mass of HCl = (1.008 + 35.45) g/mol = 36.46 g/mol
Molar mass of H₂SO₄ = (1.008×2 + 32.06 + 16.00×4) g/mol = 98.08 g/mol

2HCl + Na₂SO₄ → 2NaCl + H₂SO₄
Mole ratio HCl : H₂SO₄ = 2 : 1

No. of moles of HCl = (43.3 g) / (36.46 g/mol) = 1.188 mol
No. of moles of H₂SO₄ = (1.188 mol) × (1/2) = 0.594 mol
Mass of H₂SO₄ = (98.08 g/mol) × (0.594 mol) = 58.3 g

2 HCl + Na2SO4 → 2 NaCl + H2SO4

According to coefficients, two moles of HCl reacts with one mole of Na2SO4 to produce two moles of NaCl and one mole of H2SO4. The ratio of moles of HCl to moles of H2SO4 is 2:1. Let’s determine mass of one mole of HCl and H2SO4

HCl = 1 + 35.5 = 36.5 grams
H2SO4 = 2 + 32.1 + 4 * 16 = 98.1 grams
To determine the number of moles of HCl, divide the mass by the mass of one mole.

n = 43.3 ÷ 36.5
This is approximately 1.1863 moles.
To determine the number of moles of H2SO4, divide the number of moles of HCl by 2.

n = 21.65/36.5
To determine the mass of H2SO4, multiply this number by the mass of one mole of H2SO4.

Mass = 98.1 * 21.65/36.5 = 2123.865 ÷ 36.5

This is approximately 58.2 grams. I hope this helps you to understand how to solve this type of problem.

2 grams