According to the following reaction, how many moles of chlorine gas are necessary to form 0.970 moles phosphorus trichloride?
phosphorus (P4) (s) + chlorine (g) phosphorus trichloride (l)
According to the following reaction, how many moles of chlorine gas are necessary to form 0.970 moles phosphorus trichloride?
2016-05-30 10:50 pm
回答 (1)
2016-05-30 11:04 pm
P₄(s) + 6Cl₂(g) → 4PCl₃(l)
Mole ratio Cl₂ : PCl₃ = 6 : 4 = 3 : 2
No. of moles of PCl₃ formed = 0.970 mol
No. of moles of Cl₂ needed = (0.970 mol) × (3/2) = 1.46 mol
Mole ratio Cl₂ : PCl₃ = 6 : 4 = 3 : 2
No. of moles of PCl₃ formed = 0.970 mol
No. of moles of Cl₂ needed = (0.970 mol) × (3/2) = 1.46 mol
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