If 58.44 g of sodium chloride are dissolved in 1000.mL of H20, what is the M of the solution?
回答 (1)
2016-05-30 10:22 pm
Molar mass of NaCl = (22.99 + 35.45) g/mol = 58.44 g/mol
Number of moles of NaCl = (58.44 g) / (58.44 g/mol) = 1.000 mol
Volume of the solution = 1000 mL = 1.000 L
Molarity of NaCl = (1.000 mol) / (1.000 L) = 1.000 M
Number of moles of NaCl = (58.44 g) / (58.44 g/mol) = 1.000 mol
Volume of the solution = 1000 mL = 1.000 L
Molarity of NaCl = (1.000 mol) / (1.000 L) = 1.000 M
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