MY REVIEW FOR FINAL :(( Calculate the mass of copper produced during this reaction.?
2016-05-30 10:00 pm
Excess iron was added to 636 mL of a 0.413 M aqueous solution of copper (II) chloride producing aqueous iron(II) chloride and solid copper.
回答 (2)
2016-05-30 10:17 pm
Fe + CuCl2 → Cu + FeCl2 [balanced as written]
(0.636 L) x (0.413 mol/L CuCl2) x (1 mol Cu / 1 mol CuCl2) x (63.5463 g Cu/mol) = 16.7 g Cu
(0.636 L) x (0.413 mol/L CuCl2) x (1 mol Cu / 1 mol CuCl2) x (63.5463 g Cu/mol) = 16.7 g Cu
2016-05-30 10:06 pm
Fe(s) + CuCl₂(aq) → FeCl₂(aq) + Cu(s)
Mole ratio CuCl₂ : C山= 1 : 1
Number of moles of CuCl₂ reacted = (0.413 mol/L) × (636/1000 L) = 0.263 mol
Number of moles of Cu formed = Number of moles of CuCl₂ reacted = 0.263 mol
Mole ratio CuCl₂ : C山= 1 : 1
Number of moles of CuCl₂ reacted = (0.413 mol/L) × (636/1000 L) = 0.263 mol
Number of moles of Cu formed = Number of moles of CuCl₂ reacted = 0.263 mol
收錄日期: 2021-04-18 14:54:54
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