butane (C4H10) (g) + oxygen (g) carbon dioxide (g) + water (g)?
According to the following reaction, how many moles of carbon dioxide will be formed upon the complete reaction of 0.352 moles butane (C4H10) with excess oxygen gas?
回答 (1)
2C₄H₁₀(g) + 13O₂(g) → 8CO₂(g) + 10H₂O(g)
Mole ratio C₄H₁₀ : CO₂ = 2 : 8 = 1 : 4
Number of moles of C₄H₁₀ reacted = 0.352 mol
Number of moles of CO₂ formed = (0.352 mol) × 4 = 1.41 mol (3 sig. fig.)
收錄日期: 2021-04-18 14:55:31
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