According to the following reaction, how many grams of sodium iodide are necessary to form 0.356 moles sodium chloride?
回答 (2)
2016-05-30 9:43 pm
Cl2 + 2 NaI → 2 NaCl + I2
(0.356 mol NaCl) x (2 mol NaI / 2 mol NaCl) x (149.894 g NaI/mol) = 53.4 g NaI
(0.356 mol NaCl) x (2 mol NaI / 2 mol NaCl) x (149.894 g NaI/mol) = 53.4 g NaI
2016-05-30 9:41 pm
Cl₂(g) + 2NaI(s) → 2NaCl(s) + I₂(s)
Mole ratio NaI : NaCl = 2 : 2 = 1 : 1
Number of moles of NaCl formed = 0.356 mol
Number of moles of NaI needed = Number of moles of NaCl formed = 0.356 mol
Mole ratio NaI : NaCl = 2 : 2 = 1 : 1
Number of moles of NaCl formed = 0.356 mol
Number of moles of NaI needed = Number of moles of NaCl formed = 0.356 mol
收錄日期: 2021-04-18 14:53:41
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