Simplify (4x^-2)^2/2x^3 using positive exponents. Please?
回答 (4)
2016-05-30 7:31 pm
[4 x^(-2)]^2 / (2 x^3)
= 4^2 [x^(-2)]^2 / (2 x^3)
= 16 x^(-4) / (2 x^3)
= (16/2) x^(-4-3)
= 8 x^(-7)
= 8 / x^7
= 4^2 [x^(-2)]^2 / (2 x^3)
= 16 x^(-4) / (2 x^3)
= (16/2) x^(-4-3)
= 8 x^(-7)
= 8 / x^7
2016-05-30 7:30 pm
I assume you actually mean: (4x^−2)^2/(2x^3)
Parentheses make a difference. Please use them.
(4x⁻²)²/(2x³)
= 4²(x⁻²)²/(2x³)
= 16x⁻⁴/(2x³)
= (16/2) (x⁻⁴/x³)
= 8x⁻⁷
= 8/x⁷
2016-05-30 10:41 pm
8/x^7
2016-05-30 8:00 pm
16 x^(-4)
------------
2 x^3
8
-----
x^7
------------
2 x^3
8
-----
x^7
收錄日期: 2021-04-18 15:00:01
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160530112639AAInUtO