temperature of 58 g of water from 4.6◦C to 81◦C. How much heat is needed to accomplish this? The specific heat of water is 4180 J/kg?
回答 (1)
2016-05-30 7:02 pm
Mass of water, m = 58 g = 0.058 kg
Specific heat of water, c = 4180 J / (kg °C)
Temperature change, ΔT = (81 - 4.6)°C
Heat needed
= m c ΔT
= (0.058 kg) × [4180 J / (kg °C)] × [(81 - 4.6)°C]
= 18500 J
= 18.5 kJ
Specific heat of water, c = 4180 J / (kg °C)
Temperature change, ΔT = (81 - 4.6)°C
Heat needed
= m c ΔT
= (0.058 kg) × [4180 J / (kg °C)] × [(81 - 4.6)°C]
= 18500 J
= 18.5 kJ
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