X^2 + 5x - 5 = 3x + 10
X^2 + 7x + 24 = -2x + 4
How can I place these equations in standard form and solve for x
How to solve these equations?
2016-05-30 6:54 pm
回答 (2)
2016-05-30 7:27 pm
✔ 最佳答案
x² + 5x - 5 = 3x + 10x² + 5x - 5 - 3x - 10 = 0
x² + 2x - 15 = 0
(x + 5)(x - 3) = 0
x + 5 = 0 or x - 3 = 0
x = -5 or x = 3
====
x² + 7x + 24 = -2x + 4
x² + 7x + 24 + 2x - 4 = 0
x² + 9x + 20 = 0
(x + 4)(x + 5) = 0
x + 4 = 0 or x + 5 = 0
x = -4 or x = -5
2016-05-30 8:38 pm
1.
x² + 2x - 15 = 0
[ x + 5 ] [ x - 3 ] = 0
x = - 5 , x = 3
2.
x² + 9x + 20 = 0
[ x + 5 ] [ x + 4 ] = 0
x = - 5 , x = - 4
x² + 2x - 15 = 0
[ x + 5 ] [ x - 3 ] = 0
x = - 5 , x = 3
2.
x² + 9x + 20 = 0
[ x + 5 ] [ x + 4 ] = 0
x = - 5 , x = - 4
收錄日期: 2021-04-18 14:55:45
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