A. 1000
B. 2000
C. 500
D. 5000
If 1000 J of energy is required to raise 0.5 kg by 1 Celsius, what is the magnitude of the specific heat capacity of the material?
2016-05-30 9:37 am
回答 (2)
2016-05-30 9:45 am
Heat gain = m c ΔT
1000 J = (0.5 kg) × c × (1°C)
c = 2000 J / (kg °C)
The answer is : B. 2000
1000 J = (0.5 kg) × c × (1°C)
c = 2000 J / (kg °C)
The answer is : B. 2000
2016-05-30 9:44 am
1000 J is needed to heat 0.5 kg by 1 C°, so 2000 J is needed to heat 1.0 kg by 1 C°.
This is then 2000 J/(kg·C°), answer B.
This is then 2000 J/(kg·C°), answer B.
收錄日期: 2021-04-18 14:57:33
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