1 mole of carbon dioxide occupies 24dm³ at rtp?

Assuming that carbon dioxide is an ideal gas, 1 mole of carbon dioxide occupies approximately 24 dm³ at rtp.

1 mole of ideal gas at rtp :
P = 101.3 kPa
n = 1 mol
R = 8.314 J / (mol K)
T = 298 K
V = ?

Apply ideal gas law : PV = nRT
Thus : V = nRT/P

Volume of 1 mole of carbon dioxide (ideal gas) at rtp
= 1 × 8.314 × 298 / 101.3 dm³
= 24 dm³ (to 2 sig. fig.)


(The molecular size of carbon dioxide is rather great. Therefore, the volume of real gas of carbon dioxide deviates significantly from that of ideal gas.)

Yes it can. At STP as well.