Every way I've tried to sold the problem isn't working. The options are:
A. 2x-y=3
B. x+2y=3
C. x+y=3
D. 2x+y=5
E. x-y=3
What is the equation of the line that passes through the point (3,0) and is perpendicular to the line 2x-y=5?
2016-05-27 5:03 pm
回答 (3)
2016-05-27 5:08 pm
Slope of the line (2x - y = 5)
= -2/(-1)
= 2
Due to perpendicular :
(Slope of the required line) × 2 = -1
Slope of the required line = -1/2
Point-slope form of the required line :
y - 0 = (-1/2)(x - 3)
2y = -(x - 3)
2y = -x + 3
x + 2y = 3
...... The answer is : B. x + 2y = 3
= -2/(-1)
= 2
Due to perpendicular :
(Slope of the required line) × 2 = -1
Slope of the required line = -1/2
Point-slope form of the required line :
y - 0 = (-1/2)(x - 3)
2y = -(x - 3)
2y = -x + 3
x + 2y = 3
...... The answer is : B. x + 2y = 3
2016-05-28 3:46 pm
The answer is B since the slope of x+2y=3 is
-1/2 and the slope os 2x-y=6 is 2 and
(-1/2)(2)=-1. Also (3,0) lies on line B.
-1/2 and the slope os 2x-y=6 is 2 and
(-1/2)(2)=-1. Also (3,0) lies on line B.
2016-05-27 5:06 pm
2x - y = 5
-y = -2x + 5
y = 2x - 5
given slope is 2
perp slope is -1/2
y - 0 = (-1/2)(x - 3)
y = (-x + 3) / 2
2y = -x + 3
x + 2y = 3
-y = -2x + 5
y = 2x - 5
given slope is 2
perp slope is -1/2
y - 0 = (-1/2)(x - 3)
y = (-x + 3) / 2
2y = -x + 3
x + 2y = 3
收錄日期: 2021-04-18 14:53:56
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