Calculate ?H for the following reaction of nitrous oxide with oxygen.?

👨🏻‍🏫 學術台化學

[匿名]

2016-05-25 4:24 pm

2NO(g) + O^2(g) --> 2NO^2(g)?Hf^0 NO(g) = 90.37 kJ/mol; ?Hf^0 NO^2 (g) = 33.85 kJ/mol

回答 (2)

不用客氣

2016-05-25 4:52 pm

2NO(g) + O₂(g) → 2NO₂(g) ...... ΔH

ΔH
= 2 ΔHf[NO₂(g)] - 2 ΔHf[NO(g)] - ΔHf[O₂(g)]
= (2 × 33.85 - 2 × 90.37 - 0) kJ
= -113.04 kJ

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hcbiochem

2016-05-25 4:39 pm

Delta Hrxn = 2(Delta Hf(NO2)) - 2(Delta Hf(NO)
Delta Hrxn = 2(33.85 kJ/mol) - 2(90.37 kJ/mol) = -113.04 kJ

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