K=0.0900, h2o= 0.49 M. And hocl= 0.042 M, What is the equilibrium concentration of Cl2O?

The equation is : Cl₂O(g) + H₂O(g) ⇌ 2HOCl(g) ...... K

K = [HOCl]²/ ([Cl₂O] [H₂O])
Then, [Cl₂O] = [HOCl]²/ (K [H₂O])

At equilibrium, [Cl₂O]
= (0.042)² / (0.0900 × 0.49)
= 0.040 mol/L