I have a question on chemistry and I really need help. Any help is appreciated. Thank you.
Calculate the pressure of a 1.2g sample of carbon dioxide when confined to 500mL at 27.2 degrees C.
I need help..! Chemistry?
2016-05-25 5:01 am
回答 (2)
2016-05-25 6:31 am
✔ 最佳答案
For carbon dioxide :Mass, m = 1.2 g
Molar mass, M = (12.01 + 16.00×2) = 44.01 g/mol
No. of moles, n = 1.2/44.01 g/mol
V = 500/1000 L = 0.5 L
R = 0.0821 atm L / (mol K)
T = (273.2 + 27.2) K = 300.4 K
P = ? atm
PV = nRT
P = nRT/V
Pressure, P = (1.2/44.01) × 0.0821 × 300.4 / 0.5 atm = 1.34 atm
2016-05-25 8:50 am
Use the Ideal Gas Equation
PV = nRT
P = nRT/V
n(moles CO2) = 1.2g / 44 = 0.02727...
R(The Gas constant) = 8.314...
T(Temperature in Kelvin) = 300.2K
V (volume in m^3) = 500 mL = 0.5 dm^3 = 5.0 x 10^-4 m^3
Substitute in
P = 0.02727...x 8,314 x 300.2 / 5.0 x 10^-4
P = 136124.357 Pa.(Pascals) =( kg m s^-2 / m^2)
P 1.34344.. atms.
PV = nRT
P = nRT/V
n(moles CO2) = 1.2g / 44 = 0.02727...
R(The Gas constant) = 8.314...
T(Temperature in Kelvin) = 300.2K
V (volume in m^3) = 500 mL = 0.5 dm^3 = 5.0 x 10^-4 m^3
Substitute in
P = 0.02727...x 8,314 x 300.2 / 5.0 x 10^-4
P = 136124.357 Pa.(Pascals) =( kg m s^-2 / m^2)
P 1.34344.. atms.
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