what is the number of kilograms of solvent in a 0.70 molal solution containing 5.0 g of solute molar mass os solute is 30 g?
回答 (1)
2016-05-25 7:22 am
No. of moles of solute = (5.0 g) / (30 g/mol) = 1/6 mol
Molality = (No. of moles of solute) / (Mass of solvent in kg)
Hence, Mass of solvent in kg = (No. of moles of solute) / (Molality)
Mass of solvent
= (1/6 mol) / (0.70 mol/kg)
= 0.238 kg
Molality = (No. of moles of solute) / (Mass of solvent in kg)
Hence, Mass of solvent in kg = (No. of moles of solute) / (Molality)
Mass of solvent
= (1/6 mol) / (0.70 mol/kg)
= 0.238 kg
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