1) A chemist makes a stock solution of KOH by dissolving 1050.0g KOH in enough distilled water to make 1.50 L solution.
A. what is the concentration of the stock solution of KOH?
B. If later on the chemist wants to use this stock solution to make a 200.0mL of 0.10 M KOH, what would he need to make it? (include the base and the water) include formula if there is one
Chemistry Homework Help!?
2016-05-24 5:59 pm
回答 (1)
2016-05-24 6:13 pm
✔ 最佳答案
1)A.
Molar mass of KOH = (39.01 + 16.00 + 1.01) g/mol = 56.02 g/mol
No. of moles of KOH = (1050.0 g) / (56.02 g/mol) = 18.743 mol
Concentration of the stock solution = (18.743 mol) / (1.50 L) = 12.50 M
B.
M₁V₁ = M₂V₂
(12.50 M) × V₁ = (0.10 M) × (200.0 mL)
Volume of stock solution needed, V₁ = 0.10 × 200.0 / 12.50 = 1.6 mL
Volume of water needed = (200.0 - 1.6) = 198.4 mL
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