Chemistry Homework Help?
2016-05-23 6:00 pm
9) A chemistry student titrated 150mL of NaOH solution wiht a 2.5M HCL solution. It required 61.4 mL of acid to reach the endpoint. What was the concentration of the NaOH solution? show formula
回答 (1)
2016-05-23 6:21 pm
✔ 最佳答案
No. of moles of HCl = (2.5 mol/L) × (61.4/1000 L) = 0.1535 molHCl + NaOH → NaCl + H₂O
No. of moles of NaOH = No. of moles of HCl = 0.1535 mol
Concentration of NaOH = (0.1535 mol) / (150/1000 L) = 1.02 M
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