can 156 be divisible by 2,3,5,9 and 10?
回答 (10)
The term "divisible" means that the quotient is an integer and the remainder is 0.
156 ÷ 2 = 78
156 ÷ 3 = 52
156 ÷ 5 = 31 ...... remainder = 1
156 ÷ 9 = 17 ...... remainder = 3
156 ÷ 10 = 15 ...... remainder = 6
Hence, 156 is divisible by 2 and 3,
but not divisible by 5, 9 and 10.
Can 156 be divisible by 2,3,5,9 and 10?
Well obviously 2 because the end digit ends in 6...and is an even number.
For 3 indeed it is because the sum of digits (1 + 5 + 6 = 12) is a multiple of 3...
For 5 no it is not because it doesn't end in 0 or 5...
For 9 it is not...no it is not since the sum of digits (12) isn't divisible by 9...
For 10 heck no, because the last digit isn't 0...
No, 156 divisible by 2,3 only
It is only divisible by 2 and 3
yes, but only 2 and 3 evenly.
In order for a certain number to be a factor of a certain number, it must go into the number evenly.
(Don't mistake the hyphens as negative signs.)
156
------
1-156
2-78
3-52
4-39
6-26
12-13
2 yes as it is even number
10 no as it does not end in0
5 no as it does not end in 0 or 5
3 yes 15/3 =5 6/ = 2
9 no 15/9 1 remainder 6 66 does not divide by 9
shouldnt take a genius to figure out that only numbers ending in '0' are divisible by 10
If it's a question where decimals are acceptable then yes.
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