how many grams of NaCl would be formed from 100 grams of Na2CO3 in following reaction? Na2CO3 + 2HCl = 2NaCl + CO2 + H2O?
回答 (1)
2016-05-23 4:56 pm
Molar mass of Na₂CO₃ = (22.99×2 + 12.01 + 16.00×3) g/mol = 105.99 g/mol
No. of moles of Na₂CO₃ used = (100 g) / (105.99 g/mol) = 0.943 mol
Na₂CO₃ + 2HCl → 2NaCl + CO₂ + H₂O
Mole ratio Na₂CO₃ : NaCl = 1 : 2
No. of moles of NaCl formed = (0.943 mol) × 2 = 1.89 mol
Molar mass of NaCl = (22.99 + 35.45) g/mol = 58.44 g/mol
Mass of NaCl formed = (58.44 g/mol) × (1.89 mol) = 110 g
No. of moles of Na₂CO₃ used = (100 g) / (105.99 g/mol) = 0.943 mol
Na₂CO₃ + 2HCl → 2NaCl + CO₂ + H₂O
Mole ratio Na₂CO₃ : NaCl = 1 : 2
No. of moles of NaCl formed = (0.943 mol) × 2 = 1.89 mol
Molar mass of NaCl = (22.99 + 35.45) g/mol = 58.44 g/mol
Mass of NaCl formed = (58.44 g/mol) × (1.89 mol) = 110 g
收錄日期: 2021-05-01 15:12:16
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