For the reaction Cl2 + 2KBr -> 2KCl + Br2 How many grams of potassium chloride can be produced from 17.2 grams of potassium bromide?

Molar mass of KBr = 39.01 + 79.90 = 118.91 g/mol
No. of moles of KBr used = (17.2 g) / (118.91 g/mol) = 0.145 mol

Cl₂ + 2KBr → 2KCl + Br₂
Mole ratio KBr : KCl = 2 : 2 = 1 : 1
No. of moles of KCl produced = 0.145 mol

Molar mass of KCl = 39.01 + 35.45 = 74.46 g/mol
Mass of KCl = (74.46 g/mol) × (0.145 mol) = 10.8 g