So Log₂(a) = w, by definition of Log₂, a = 2^w
更新1:
I know the answer which is √2w just not how to set up the problem to get me to the answer
Let w= log base 2 of a? solve the expressions in terms of w?
回答 (2)
2016-05-20 7:41 pm
Actually, you already know the answer,
w = log_base2 a,
means, a = 2^w, thus, you have a in terms of w.
You solved it!
w = log_base2 a,
means, a = 2^w, thus, you have a in terms of w.
You solved it!
2016-05-20 7:21 pm
w = log₂(a)
Do you mean √(log₂(a²)) = √2w, or √(log₂(a²)) = √(2w) ?
√(log₂(a²)) = √(2w)
square both sides
log₂(a²) = 2w
2log₂(a) = 2w
log₂(a) = w
a = 2^w
Do you mean √(log₂(a²)) = √2w, or √(log₂(a²)) = √(2w) ?
√(log₂(a²)) = √(2w)
square both sides
log₂(a²) = 2w
2log₂(a) = 2w
log₂(a) = w
a = 2^w
收錄日期: 2021-04-21 18:41:23
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