Find tan1°.tan2°....tan88°.tan89° Thanks?

2016-05-19 10:49 am

回答 (3)

2016-05-19 12:42 pm
✔ 最佳答案
tan1°.tan2°....tan88°.tan89°
(tan1°tan89°)(tan2°.tan88°).................(tan43°.tan47°)(tan44°.tan46°)....tan45°
We know that
tan(90−x)=cotx
Hence tan89° =cot1° →(tan1°tan89°)=1
tan88° =cot2° →(tan 2°tan88°) =1and so on
Hence
(tan1°tan89°)(tan2°.tan88°).................(tan43°.tan47°)(tan44°.tan46°)tan45°
=(1)(1).................(1)(1)×1
=1
2016-05-19 12:31 pm
tan(90-x) = cot(x)

tan(89°) = cot(1°)
tan(88°) = cot(2°)
.....
.....
tan(46°) = cot(44°)
tan(45°)= cot(45°) = 1

tan 1°.tan2°....tan88°.tan89° = tan 1° tan°2°.....tan 44° 1 cot 44° cot°43....cot 1°
= 1
2016-05-19 11:16 am
Set your calculator to degree mode.
Type in 1.
Hit the tan button.
Type in 2.
Hit the tan button.
Type in 3...


收錄日期: 2021-05-01 20:42:37
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