How to solve these algebra problems?

2x^2+7x+4=0

x= -7+√ (7)²- (4)(2)(4) x= -7-√ (7)²- (4)(2)(4)
(2)(2) (2)(2)
x= -7+(4.12) x= -7-(4.12)
4 4
x= -7/4 + (√17/4) x= -7/4 - (√17/4)

x= -0.72 x= -2.78



2x^2 + 4x + 10

x= -4+√ (4)²- (4)(2)(10) x= -4-√ (4)²- (4)(2)(10)
(2)(2) (2)(2)
x= -1 + (2i) x= -1 - (2i)

x= No Real Solution x= No Real Solution
Imaginary: -1 + (2i ) Imaginary: -1 - (2i )

somebody didnt pay attention while they were teaching the quadratic formula or else this would be super easy
use 2 as A, 7 as B and 4 as C
then do x= -B +- (sqrt(B^2 - 4*A*C)/2A)