In 2.76g of AgCO3 are strongly heated find the mass of Ag formed?
回答 (1)
2016-05-17 3:59 pm
The formula of silver carbonate should be Ag₂CO₃ instead.
In 1 mole of Ag₂CO₃ :
Total mass of Ag₂CO₃ = (108×2 + 12.0 + 16×3) g = 276 g
Mass of Ag contained = 108×2 = 216 g
Mass of Ag formed = (2.76 g) × (216/276) = 2.16 g
In 1 mole of Ag₂CO₃ :
Total mass of Ag₂CO₃ = (108×2 + 12.0 + 16×3) g = 276 g
Mass of Ag contained = 108×2 = 216 g
Mass of Ag formed = (2.76 g) × (216/276) = 2.16 g
收錄日期: 2021-04-18 14:50:17
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