CHEM (Equilibrium) In water, the following equilibrium exists: H+(aq) + OH-(aq) <--> H2O(l) In pure water at 25 °C, the concentration of?
2016-05-17 9:04 am
In water, the following equilibrium exists: H+(aq) + OH-(aq) <--> H2O(l) In pure water at 25 °C, the concentration of H+ ions is 1.00 * 10-7 mol/L. Calculate the value of the equilibrium constant for the reaction as written above. A) 1.00 * 1014 B) 1.00 * 1012 C) 1.00 * 10-14 D) 1.00 * 10-12 E) 5.55 * 1015
回答 (1)
2016-05-17 9:13 am
H⁺(aq) + OH⁻(aq) ⇌ H₂O(l)
[H⁺] = 1.00 × 10⁻⁷ mol/L
As water is neutral, [OH⁻] = [H⁺] = 1.00 × 10⁻⁷ mol/L
The equilibrium constant for the above reaction
= 1 / ([H⁺][OH⁻])
= 1 / (1.00 × 10⁻⁷)²
= 1 / 1.00 × 10⁻¹⁴
= 1.00 × 10¹⁴
...... The answer is: A) 1.00 × 10¹⁴
[H⁺] = 1.00 × 10⁻⁷ mol/L
As water is neutral, [OH⁻] = [H⁺] = 1.00 × 10⁻⁷ mol/L
The equilibrium constant for the above reaction
= 1 / ([H⁺][OH⁻])
= 1 / (1.00 × 10⁻⁷)²
= 1 / 1.00 × 10⁻¹⁴
= 1.00 × 10¹⁴
...... The answer is: A) 1.00 × 10¹⁴
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