函數f(x)=-1則f(1)+2f(2)+3f(3)=?已知f(x)=3x+1/2則f(-3)+f(5)=?設f(x)=-2+1g(x)=4x+9若(2a)=g(a)則 a=？若f(x)=5x+1且f(a+1)=16則 f(a)=?

f(x)=-1
f(1)+2f(2)+3f(3)
=-1-2-3
=-6

f(x)=3x+1/2
f(-3)+f(5)
=-6+15+1
=10

f(x)=-2+1=-1
g(x)=4x+9
f(2a)=g(a)
-1=4a+9
4a=-10
a=-2.5

f(x)=5x+1
f(a+1)=5(a+1)+1
16=5a+5+1
5a=10
a=2
f(a)=f(2)=5(2)+1=11