Calculate the number of moles of solute in 79.33 mL of 0.1455 M K2Cr2O7(aq).?
回答 (2)
2016-05-12 8:04 pm
The solute is K₂Cr₂O₇.
No. of moles of K₂Cr₂O₇ = (0.1455 mol/L) × (79.33/1000 L) = 0.01154 mol
No. of moles of K₂Cr₂O₇ = (0.1455 mol/L) × (79.33/1000 L) = 0.01154 mol
收錄日期: 2021-04-18 14:53:11
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