Diamond crystallizes in a cubic lattice with an edge length of 357 pm.?
2016-05-12 9:52 am
If there are a total of 8 carbon atoms in the unit cell, what is the density of diamond?
回答 (1)
2016-05-12 10:13 am
Volume of a unit cell
= (357 pm)³
= (357 × 10⁻¹⁰ cm)³
= 4.550 × 10⁻²³ cm³
6.022 × 10²³ (1 mole) carbon atoms has a mass of 12.01 g.
Mass of a unit cell (8 carbon atoms)
= [(12.01 g / mol) / (6.022 × 10²³ atoms/mol)] × (8 atoms)
= 1.595 × 10⁻²² g
Density of diamond
= Mass / Volume
= (1.595 × 10⁻²² g) / (4.550 × 10⁻²³ cm³)
= 3.51 g/cm³
= (357 pm)³
= (357 × 10⁻¹⁰ cm)³
= 4.550 × 10⁻²³ cm³
6.022 × 10²³ (1 mole) carbon atoms has a mass of 12.01 g.
Mass of a unit cell (8 carbon atoms)
= [(12.01 g / mol) / (6.022 × 10²³ atoms/mol)] × (8 atoms)
= 1.595 × 10⁻²² g
Density of diamond
= Mass / Volume
= (1.595 × 10⁻²² g) / (4.550 × 10⁻²³ cm³)
= 3.51 g/cm³
收錄日期: 2021-05-01 13:08:15
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160512015211AAlPXDA