initial pressure : 2.0 atm
initial volume : 5.0 L
initial temperature : 215 K
What is the pressure of the ideal gas n the volume is decreased to 4.0 L and the temperature is increased to 265 K?
2016-05-11 6:09 pm
回答 (1)
2016-05-11 6:26 pm
Initial : P₁ = 2.0 atm, V₁ = 5.0 L, T₁ = 215 K
Final : P₂ = ? atm, V₂ = 4.0 L, T₂ = 265 K
P₁V₁/T₁ = P₂V₂/T₂
P₂ = P₁V₁T₂/(V₂T₁)
Final pressure, P₂ = 2.0 × 5.0 × 265 / (4.0 × 215) = 3.08 atm
Final : P₂ = ? atm, V₂ = 4.0 L, T₂ = 265 K
P₁V₁/T₁ = P₂V₂/T₂
P₂ = P₁V₁T₂/(V₂T₁)
Final pressure, P₂ = 2.0 × 5.0 × 265 / (4.0 × 215) = 3.08 atm
收錄日期: 2021-04-18 14:54:48
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160511100937AABVSJ1