A sample of oxygen gas occupies a volume of 6.03 L at 52 °C and 0.891 atm.
If it is desired to increase the volume of the gas sample to 8.98 L, while decreasing its pressure to 0.546 atm, the temperature of the gas sample at the new volume and pressure must be ______ °C.
A sample of oxygen gas occupies a volume of 6.03 L at 52 °C and 0.891 atm.?
2016-05-10 2:52 pm
回答 (1)
2016-05-10 3:05 pm
✔ 最佳答案
Original : P₁ = 0.891 atm, V₁ = 6.03 L, T₁ = (273 + 52) K = 325 KAfter change : P₂ = 0.546 atm, V₂ = 8.98 L, T₂ = ? K
For a fixed amount of gas :
P₁V₁/T₁ = P₂V₂/T₂
T₂ = T₁ × (P₂/P₁) × (V₂/V₁)
New temperature, T₂
= (325 K) × (0.546/0.891) × (8.98/6.03)
= 296.6 K
= (296.6 - 273)°C
= 23.6°C
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