For each 2.00mol of NH3 reacted?
Please help. This is stoichiometry and Sig fig stuff I'm bad at. Please show the work. Please help.
How many liters of hydrogen are required to produce 2.8 liters of ammonia? N2(g)+3H2(g)-->2NH3(g) How many molecules of H2O are produced?
2016-05-10 2:41 pm
回答 (1)
2016-05-10 2:56 pm
How many liters of hydrogen are required to produce 2.8 liters of ammonia?
N₂(g) + 3H₂(g) → 2NH₃(g)
Under constant pressure and temperature, volume ratio H₂ : NH₃ = 3 : 2
Volume of NH₃ produced = 2.8 L
Volume of H₂ produced = (2.8 L) × (3/2) = 4.2 L
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How many molecules of H₂O are produced for each 2.00mol of NH₃ reacted?
2NH₃ + ...... → 3H₂O + ......
Mole ratio NH₃ : H₂O = 4 : 6 = 2 : 3
No. of moles of NH₃ reacted = 2.00 mol
No. of moles of H₂O produced = (2.00 mol) × (3/2) = 3.00 mol
1 moles H₂O contains 6.022 × 10²³ molecules.
No. of H₂O molecules produced = (6.022 × 10²³ /mol) × (3.00 mol) = 1.81 × 10²⁴
N₂(g) + 3H₂(g) → 2NH₃(g)
Under constant pressure and temperature, volume ratio H₂ : NH₃ = 3 : 2
Volume of NH₃ produced = 2.8 L
Volume of H₂ produced = (2.8 L) × (3/2) = 4.2 L
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How many molecules of H₂O are produced for each 2.00mol of NH₃ reacted?
2NH₃ + ...... → 3H₂O + ......
Mole ratio NH₃ : H₂O = 4 : 6 = 2 : 3
No. of moles of NH₃ reacted = 2.00 mol
No. of moles of H₂O produced = (2.00 mol) × (3/2) = 3.00 mol
1 moles H₂O contains 6.022 × 10²³ molecules.
No. of H₂O molecules produced = (6.022 × 10²³ /mol) × (3.00 mol) = 1.81 × 10²⁴
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