0.675 mol of K3PO4 causes complete precipitation of all of the calcium. How many moles of calcium were dissolved in the solution? mass?
回答 (1)
2016-05-10 8:00 am
3Ca²⁺(aq) + 2PO₄³⁻(aq) → Ca₃(PO₄)₂(s)
Mole ratio Ca²⁺(aq) : PO₄³⁻ = 3 : 2
No. of moles of PO₄³⁻ ions = No. of moles of K₃PO₄ = 0.675 mol
No. of moles of Ca²⁺ ions dissolved in the solution = (0.675 mol) × (3/2) = 1.0125 mol
Molar mass of Ca²⁺ ions = 40.08 g/mol
Mass of Ca²⁺ ions dissolved in the solution = (40.08 g/mol) × (1.0125 mol) = 40.58 g
Mole ratio Ca²⁺(aq) : PO₄³⁻ = 3 : 2
No. of moles of PO₄³⁻ ions = No. of moles of K₃PO₄ = 0.675 mol
No. of moles of Ca²⁺ ions dissolved in the solution = (0.675 mol) × (3/2) = 1.0125 mol
Molar mass of Ca²⁺ ions = 40.08 g/mol
Mass of Ca²⁺ ions dissolved in the solution = (40.08 g/mol) × (1.0125 mol) = 40.58 g
收錄日期: 2021-04-18 14:48:53
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