Finding The Initial I- Concentration In A solution Please Help with exaplin?

Method I :

In 3.0 mL of 0.20 M KI solution, the number of moles of I⁻
= The number of moles of KI
= Molarity × (Volume of solution)
= (0.20 mol/L) × (3.0/1000 L)
= 0.00060 mol

After mixing the solutions, the total volume
= (3.0 + 5.0 + 5.0 + 6.0 + 1.0) mL
= 20 mL
= 0.020 L

[I⁻] in the mixture solution
= moles / volume
= (0.00060 mol) / (0.020 L)
= 0.03 M


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Method 2 :

M1 V₁ = M₂ V₂
M₂ = M₁ V₁ / V₂

Final concentration of I⁻, V₂
= 0.20 × 3.0 / (3.0 + 5.0 + 5.0 + 6.0 + 1.0) M
= 0.03 M