Please help and if you can can you show the steps.?
2016-05-10 6:03 am
Bruce is titrating 5mL of vinegar of unknown concentration. If it takes 20.95mL of NaOH of concentration .2M to reach the equivalence point, what is the concentration of acetic acid.
回答 (1)
2016-05-10 7:23 am
✔ 最佳答案
CH₃COOH + NaOH → CH₃COONa + H₂OMole ratio CH₃COOH : NaOH = 1 : 1
Number of moles of NaOH = (0.2 mol/L) × (20.95/1000 L) = 0.00419 mol
Number of moles of CH₃COOH = 0.00419 mol
Concentration of CH₃COOH = (0.00419 mol) / (5/1000 L) = 0.838 M
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