determine the pH of a solution of 0.11M HNO3 include equation, substitution, and answer?
回答 (1)
2016-05-10 9:17 am
[HNO₃] = 0.11 M
HNO₃ is strong monoprotic acid, which completely dissociates to give H⁺ ions.
HNO₃(aq) → H⁺(aq) + NO₃⁻(aq)
Hence, [H⁺] = 0.11 M
pH = -log[H⁺] = -log(0.11) = 0.96
HNO₃ is strong monoprotic acid, which completely dissociates to give H⁺ ions.
HNO₃(aq) → H⁺(aq) + NO₃⁻(aq)
Hence, [H⁺] = 0.11 M
pH = -log[H⁺] = -log(0.11) = 0.96
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