It is found that a sample of magnesium oxide consists of 4.04 g of Mg and 2.66 g of O. Calculate the empirical formula.?
回答 (1)
2016-05-10 10:12 am
Molar mass of Mg = 24.3 g/mol
Molar mass of O = 16.0 g/mol
Mole ratio Mg : O
= 4.04/24.3 : 2.66/16.0
= 0.166 : 0.166
= 1 : 1
Empirical formula = MgO
Molar mass of O = 16.0 g/mol
Mole ratio Mg : O
= 4.04/24.3 : 2.66/16.0
= 0.166 : 0.166
= 1 : 1
Empirical formula = MgO
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