The concentration of HNO3 in a solution is 5.60 ✕ 10-6 M.
What is the [H3O+] in the solution?
What is the [OH-] in the solution?
What is the pH of the solution?
What is the pOH of the solution?
Chemistry help?
2016-05-10 4:04 am
回答 (1)
2016-05-10 10:31 am
HNO₃ is a strong monoprotic acid, which completely dissociates in water to give H₃O⁺ ions.
HNO₃(aq) + H₂O(l) → H₃O⁺(aq) + NO₃⁻(aq)
Hence, [H₃O⁺] = [HNO₃] = 5.60 × 10⁻⁶ M
Kw = [H₃O⁺] [OH⁻]
(1.00 × 10⁻¹⁴ M²) = (5.60 × 10⁻⁶ M) × [OH⁻]
[OH⁻] = (1.00 × 10⁻¹⁴ M²) / (5.60 × 10⁻⁶ M) = 1.79 × 10⁻⁹ M
pH = -log[H₃O⁺] = -log(5.60 × 10⁻⁶) = 5.25
pOH = -log[OH⁻] = -log(1.79 × 10⁻⁹) = 8.75
HNO₃(aq) + H₂O(l) → H₃O⁺(aq) + NO₃⁻(aq)
Hence, [H₃O⁺] = [HNO₃] = 5.60 × 10⁻⁶ M
Kw = [H₃O⁺] [OH⁻]
(1.00 × 10⁻¹⁴ M²) = (5.60 × 10⁻⁶ M) × [OH⁻]
[OH⁻] = (1.00 × 10⁻¹⁴ M²) / (5.60 × 10⁻⁶ M) = 1.79 × 10⁻⁹ M
pH = -log[H₃O⁺] = -log(5.60 × 10⁻⁶) = 5.25
pOH = -log[OH⁻] = -log(1.79 × 10⁻⁹) = 8.75
收錄日期: 2021-04-18 14:54:13
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160509200438AAASOZl