How many moles of oxygen may be produced from the decomposition of 3.6 moles of potassium chlorate?
回答 (1)
2016-05-09 8:33 pm
Equation for the decomposition of potassium chlorate :
2KClO₃(s) → 2KCl(s) + 3O₂(g)
According to the equation, the decomposition of 2 moles of KClO₃ gives 3 moles of O₂.
Number of moles of O₂ produced from the decomposition of 3.6 moles of KClO₃
= (3.6 mol) × (3/2)
= 5.4 mol
2KClO₃(s) → 2KCl(s) + 3O₂(g)
According to the equation, the decomposition of 2 moles of KClO₃ gives 3 moles of O₂.
Number of moles of O₂ produced from the decomposition of 3.6 moles of KClO₃
= (3.6 mol) × (3/2)
= 5.4 mol
收錄日期: 2021-04-18 14:47:32
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