Chemistry help?
2016-05-06 4:55 pm
A sample of hydrogen gas is mixed with water vapor. The mixture has a total pressure of 751 torr, and the water vapor has a partial pressure of 22 torr. What amount (in moles) of hydrogen gas is contained in 1.47 L of this mixture at 298 K?
回答 (1)
2016-05-06 5:27 pm
P = (751 - 22)/760 atm = 729/760 atm
V = 1.47 L
T = 298 K
R = 0.0821 atm L / (mol K)
n = ? mol
PV = nRT
n = PV/(RT)
No. of moles of H₂, n = (729/760) × 1.47 / (0.0821 × 298) mol = 0.0576 mol
V = 1.47 L
T = 298 K
R = 0.0821 atm L / (mol K)
n = ? mol
PV = nRT
n = PV/(RT)
No. of moles of H₂, n = (729/760) × 1.47 / (0.0821 × 298) mol = 0.0576 mol
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160506085513AAi7gAZ