how many liters of water vapor will be produced at 1.00 atm and 200 deg c by the complete combustion of 10.5 L of my methane gas?
回答 (1)
2016-05-06 3:16 pm
The equation of the complete combustion of methane :
CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)
According to the above equation, under constant temperature and pressure, the complete combustion of 1 volume of CH₄ would produce 2 volume of H₂O vapor.
Volume of CH₄ undergoes complete combustion = 10.5 L
Volume of H₂O vapor produced = 10.5 × 2 L = 21.0 L
CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)
According to the above equation, under constant temperature and pressure, the complete combustion of 1 volume of CH₄ would produce 2 volume of H₂O vapor.
Volume of CH₄ undergoes complete combustion = 10.5 L
Volume of H₂O vapor produced = 10.5 × 2 L = 21.0 L
收錄日期: 2021-04-18 14:48:53
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