Evaluate sine,cosine,tangent of the angle 7pi/6?

　
sin(7π/6) = −1/2
cos(7π/6) = −√3/2
tan(7π/6) = sin(7π/6)/cos(7π/6) = 1/√3 = √3/3

7π/6 is in Q3, directly opposite π/6
(30 degrees below negative x-axis)

Coordinates = (cos(7π/6), sin(7π/6)) = (−√3/2, −1/2)

7pi/6 = pi + pi/6 is n quad 3 where sin and cos are < 0 and tan > 0.
sin(7pi/6) = - sin(pi/6) = -(1/2). cos (7pi/6) = -cos(pi/6) = -(1/2)rt3. tan(7pi/6)=
tan(pi/6) = 1/rt3 = (1/3)rt3.

sin(7pi/6) = 1/2
cos(7pi/6) = √3/2
tan(7pi/6) = √3/3