sin?
cos?
tan?
Also show on a unit circle, or please give coordinates!
Evaluate sine,cosine,tangent of the angle 7pi/6?
2016-05-05 11:37 pm
回答 (3)
2016-05-05 11:52 pm
sin(7π/6) = −1/2
cos(7π/6) = −√3/2
tan(7π/6) = sin(7π/6)/cos(7π/6) = 1/√3 = √3/3
7π/6 is in Q3, directly opposite π/6
(30 degrees below negative x-axis)
Coordinates = (cos(7π/6), sin(7π/6)) = (−√3/2, −1/2)
2016-05-05 11:50 pm
7pi/6 = pi + pi/6 is n quad 3 where sin and cos are < 0 and tan > 0.
sin(7pi/6) = - sin(pi/6) = -(1/2). cos (7pi/6) = -cos(pi/6) = -(1/2)rt3. tan(7pi/6)=
tan(pi/6) = 1/rt3 = (1/3)rt3.
sin(7pi/6) = - sin(pi/6) = -(1/2). cos (7pi/6) = -cos(pi/6) = -(1/2)rt3. tan(7pi/6)=
tan(pi/6) = 1/rt3 = (1/3)rt3.
2016-05-05 11:39 pm
sin(7pi/6) = 1/2
cos(7pi/6) = √3/2
tan(7pi/6) = √3/3
cos(7pi/6) = √3/2
tan(7pi/6) = √3/3
收錄日期: 2021-04-21 18:29:05
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160505153744AA9DShL