Why is log(X1/X0) = log(1+((X1-X0)/Xo))
??
更新1:
Why is log(X1/X0) = log(1+((X1-X0)/X0))
logarithm question?
回答 (4)
2016-05-05 9:42 pm
Because X1/X0 = 1 +(X1 -X0)/X0
(X1 -X0)/X0 = X1/X0 -1
So 1 +(X1 -X0)/X0 = 1 +X1/X0 -1= X1/X0
(X1 -X0)/X0 = X1/X0 -1
So 1 +(X1 -X0)/X0 = 1 +X1/X0 -1= X1/X0
2016-05-05 9:40 pm
Because 1+((X1-X0)/X0) simplifies (without any logarithms) to X1/X0.
2016-05-05 9:51 pm
Idk
2016-05-05 9:37 pm
You are a pig
收錄日期: 2021-05-01 20:39:45
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160505133640AAlNtQB