How do we solve for x here? y = square root(x^2 + 4x) − x?
回答 (3)
y = square root(x^2 + 4x) − x
y + x = sqrt( x^2 + 4x)
Square both sides
( x + y)^2 = x^2 + 4x
x^2 + 2xy + y^2 = x^2 + 4x
Subtract x^2 from both sides
2xy + y^2 = 4x
2xy - 4x = - y^2
x( 2y - 4) = - y^2
x = - y^2/(2y - 4)
= y^2/(4 - 2y)
= y^2/2(2 - y)
Cannot solve for x. What do you want solved?
收錄日期: 2021-04-25 13:13:02
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160501042434AAJSfX4
檢視 Wayback Machine 備份