For the equation y= x^2 + 4 + 10, write in in the form of y=(x-h)^2+k ? (Steps please)?
回答 (8)
2016-05-01 12:33 pm
y = x² + 4x + 10
...add and subtract [x]²/4. Here [x] = 4, so [x]²/4 = 4
y = x² + 4x + 4 - 4 + 10
...first three terms complete a square (x + [x]/2)², and simplify/combine the remaining two terms
y = (x + 2)² + 6
...add and subtract [x]²/4. Here [x] = 4, so [x]²/4 = 4
y = x² + 4x + 4 - 4 + 10
...first three terms complete a square (x + [x]/2)², and simplify/combine the remaining two terms
y = (x + 2)² + 6
參考: [xⁿ]: coefficient of xⁿ
2016-05-03 7:52 am
y=(x+2)²+6
2016-05-01 8:06 pm
y = x^2 + 4x + 10
y = (x + 2)^2 + 6
y = (x + 2)^2 + 6
2016-05-01 2:06 pm
Complete the square.
Y = x^2 + 4x + 2^2 - 2^2 + 10
Y = (x+2)^2 + 6
Y = x^2 + 4x + 2^2 - 2^2 + 10
Y = (x+2)^2 + 6
2016-05-01 1:26 pm
Could it be that you mean :-
y = x² + 4x + 10
y = [ x² + 4x + 4 ] - 4 + 10
y = [ x + 2 ]² + 6
y = x² + 4x + 10
y = [ x² + 4x + 4 ] - 4 + 10
y = [ x + 2 ]² + 6
2016-05-01 12:47 pm
Complete the square.
The coefficient of x is 4.
4/2 = 2; 2² = 4
y = x² + 4x + 10 = x² + 4x + 4 + 6
y = (x+2)² + 6
h=-2, k=6
// teach a man to fish ...
The coefficient of x is 4.
4/2 = 2; 2² = 4
y = x² + 4x + 10 = x² + 4x + 4 + 6
y = (x+2)² + 6
h=-2, k=6
// teach a man to fish ...
2016-05-01 12:35 pm
y=x^2+4x+10 = x^2+4x+4 + 6
y = (x+2)^2 + 6
h=-2, k=6
y = (x+2)^2 + 6
h=-2, k=6
2016-05-01 12:18 pm
y= x² + 4x + 10
=x²+4x+4+6
=(x+2)²+6
=x²+4x+4+6
=(x+2)²+6
收錄日期: 2021-04-23 20:47:31
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