How to find parabola equation with only given vertex (0,4)?
回答 (3)
2016-05-01 11:20 am
(y-4)^2=ax where a is any constant.
2016-05-01 6:27 am
Use the formula to find the vertex, and work backwards from there:
y = a*(x-p)^2 + q, where (p,q) is the vertex, and a is any constant that is used to change the size, but not the shape, of the graph.
Subbing p = 0 and q = 4,
y = a*(x-0)^2 + 4
y = a*(x^2) + 4
You need one other point on the parabola to determine a.
Hope this helps! :)
y = a*(x-p)^2 + q, where (p,q) is the vertex, and a is any constant that is used to change the size, but not the shape, of the graph.
Subbing p = 0 and q = 4,
y = a*(x-0)^2 + 4
y = a*(x^2) + 4
You need one other point on the parabola to determine a.
Hope this helps! :)
2016-05-01 6:01 am
y=x^2+4?????!
收錄日期: 2021-04-23 20:46:05
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