C++ function string?

If you're going to use C++, let count_if and string::find do the work of iterating through the strings. Here's an example that should give you some ideas for how to write your program:

#include <iostream>
#include <string>
#include <algorithm>
#include <cctype>

using namespace std;

typedef enum {
. . Vowel, Consonant, LowerCase, UpperCase, NumCharTypes
} CHAR_TYPE;
bool isVowel(char);
bool isConsonant(char);
bool isLower(char ch) { return islower(ch); }
bool isUpper(char ch) { return isupper(ch); }
typedef bool (*charChecker)(char);
size_t charCount(const string&, charChecker);
charChecker func[] = { isVowel, isConsonant, isLower, isUpper };
string charType[] = {
. . "vowels = ", "consonants = ", "lowercase = ", "uppercase = "
};

int main(int argc, char *argv[]) {
. . string in;

. . while (true) {
. . . . cout << "\nEnter a line: ";
. . . . getline(cin, in);
. . . . cout << "Counts:\n";
. . . . for (size_t i = 0; i < NumCharTypes; i++) {
. . . . . . cout << ". " << charType[i] << charCount(in, func[i]) << "\n";
. . . . }
. . }
. . return 0;
}

bool isVowel(char ch) {
. . static const string vowels("aeiou");
. . return vowels.find(ch) != string::npos;
}

bool isConsonant(char ch) {
. . return isalpha(ch) && !isVowel(ch);
}
size_t charCount(const string &s, charChecker f) {
. . return count_if(s.begin(), s.end(), f);
}

#if 0

Sample run:

Enter a line: Hello, World! 123
Counts:
. vowels = 3
. consonants = 7
. lowercase = 8
. uppercase = 2

#endif

here is one way...

int vowelcount ( string s){
int vowels = 0;
char t;
for(int l=s.length()-1;l>=0;l--){
t=toupper(s[l]);
vowels+=(t =='A' || t=='E' || t=='I' || t=='O' || t=='U') ;
}
return vowels;
}