Calc 2 Problem. I need urgent help! Find the slope of the tangent line to the graph of the polar equation?

x = r cosθ
As r = θ, then x = 2^θ cosθ
dx/dθ = 2^θ (-sinθ) + (2^θ) ln(2) cosθ
dx/dθ = 2^θ [ln(2) cosθ - sinθ] ...... [1]

y = r sinθ
y = 2^θ sinθ
dy/dθ = 2^θ cosθ + (2^θ) ln(2) sinθ
dy/dθ = 2^θ [cosθ + ln(2) sinθ] ...... [2]

[2]/[1] :
dy/dx = [ln(2) cosθ - sinθ] / [cosθ + ln(2) sinθ]

The required slope
= dy/dx | (θ = π)
= [ln(2) cosπ - sinπ] / [cosπ + ln(2) sinπ]
= [ln(2) (-1) - 0] / [(-1) + ln(2) (0)]
= [-ln(2)] / (-1)
= ln(2)