Calculate the specific gravity of the total mixture?

Density of water
= 1 g/cm³

Volume of water
= (Mass of water) / (Density of water)
= (100 g) / (1 g/cm³)
= 100 cm³

Density of alcohol
= 790 kg/m³
= (790 × 1000 g) / (1000000 cm³)
= 0.79 g/cm³

Volume of alcohol
= (Mass of alcohol) / (Density of alcohol)
= (150 g) / (0.79 g/cm³)
= 190 cm³

Mass of the mixture
= (Mass of water) + (Mass of alcohol)
= (100 g) + (150 g)
= 250 g

Volume of the mixture
= (Volume of water) + (Volume of alcohol)
= (100 cm³) + (190 cm³)
= 290 cm³

Density of the mixture
= (Mass of the mixture) / (Volume of the mixture)
= (250 g) / (290 cm³)
= 0.862 g/cm³

Specific gravity of the mixture
= 0.862

V1 = 100 cc
V2 = 150/0.79 = 190 cc
V = V1+V2 = 100+190 = 290 cc
ρ = (m1+m2)/V = (100+150)/290 = 25/29 = 0.862 g/cm^3